Answer :

Given that,

The difference between two consecutive angles is 10^{o}.

Let, x, x + 10 and x + 20 be the consecutive angles differ by 10^{o}.

We know that,

x + x + 10 + x + 20 = 180^{o}

3x + 30^{o} = 180^{o}

3x = 180^{o} – 30^{o}

3x = 150^{o}

x = 50^{o}

Therefore, the required angles are:

x = 50^{o}

x + 10 = 50^{o} + 10^{o}

= 60^{o}

x + 20 = 50^{o} + 20^{o}

= 70^{o}

The difference between two consecutive angles is 10^{o} then three angles are 50^{o}, 60^{o} and 70^{o}.

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